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A non-conducting disk of radius `R` is rotating about its own axis with constant angular velocity `omega` in a perpendicular uniform magnetic field `B` as shown in figure. The emf induced between centre and rim of disk is A. `(B omega R^(2))/(2)`B. `B omega R^(2)`C. ZeroD. `(B omega R^(2))/(3)` |
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Answer» Correct Answer - C As the ring is non-conducting, no motion of charge carries occur and hence there is no induced emf |
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