A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 Omega is connected in the collector circuit and the voltage drop across it is 0.8 V. If the current amplification factor the voltage gain and the power gain of the amplifies will respectively be:

A npn transistor is connected in common emitter configuration in a giv

1.	A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 Omega is connected in the collector circuit and the voltage drop across it is 0.8 V. If the current amplification factor the voltage gain and the power gain of the amplifies will respectively be:
Answer» `4,3.84` `3.69,3.84` `4,4` `4,3.69` Solution :VOLTAGE gain =[current gain][resistance gain] GIVEN current gain `=ALPHA=0.96` Voltage gain for common base CONFIGURATION `A_(v)=alpha.(R_(L))/(R_(p))=0.96xx800/192=4` POWER gain for common base configuration `P_(v)=A_(v)alpha=4xx0.96=3.84`

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