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A nuclear af rest undergoes a decay emitting and alpha- particle of de-Broglie wavelength lamda=5.76xx10^(-15) meter. he mass of the daughter nucleus is 223.610 amu and that of the alpha- particle is 4.002 a.m.u. (1"amu"=931.470(MeV)/(C^(2))) The total kinetic energy of the system in the final state is ( m_(d)= mass of daughter nucleus) m_(alpha)= mass of alpha- particle |
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Answer» <P>`(P_(ALPHA)^(2)(m_(alpha)+m_(d)))/(2m_(alpha)m_(d)),(P_(d)="linear momentum of "alpha-"PARTICLE")` |
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