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A nucleus disintegrates into two nuclear parts which have their velocities in the ratio 2:1. The ratio of their nuclear sizes will be : |
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Answer» `1 : 3^(1//2)` `0=m_(1)v_(1)+m_(2)v_(2)` `m_(1)v_(1)=-m_(2)v_(2)` `m_(1)/m_(2)=-v_(2)/v_(1)=v_(2)/v_(1) ("in MAGNITUDE")` But `m_(1)/m_(2) alpha A_(1)/A_(2) alpha v_(2)/v_(1)` But `v_(2)/v_(1)=1/2 therefore A_(1)/A_(2)=1/2` `R_(1)/R_(2)=(R_(0) A_(1)^(1//3))/(R_(0) A_(2)^(1//3)) = (A_(1))/(A_(2))^(1//3) =(1/2)^(1//3)` `R_(1)/R_(2)=1/2^(1//3)=1:2^(1//3)` |
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