InterviewSolution
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InterviewSolution
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A nucleus with Z =92 emits the following in a sequence: `alpha,beta^(-),beta^(-),alpha,alpha,alpha,alpha,alpha,beta^(-),beta^(-),alpha,beta^(+),beta^(+),alpha`. The Z of the resulting nucleus isA. `76`B. `78`C. `82`D. `74` |
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Answer» Correct Answer - B `8 alpha` have been emitted `4 beta^(-)` have been emitted `2 beta^(+)` have emitted `alpha` reduces atomic number by 2 `beta^(-)` increases atomic number by 1 `beta^(+)` increases by 1 So, `Z_(eff) = 92 - (8 xx 2) + (4 xx 1) - (2 xx 1) = 96 - 18 = 78` |
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