1.

A nucleus X of mass M. intially at rest undergoes alpha decay according to the equation _(Z)^(A)Xrarr._(Z-2)^(A-4)Y+._(2)^(4)He The alpha particle emitted in the above proces is found to move in a circular track of radius r in a uniform magnetic field B. Then (mass and charge of alpha particle are m and q respectively)

Answer»

The ratio of kinetic energies of the alpha particle and (doughether NUCLEUS Y approximately equals `(M-m)/(m)`
the ratio of kinetic energies of the alpha particle and the doughter nucleus Y apporximately `(m)/(M)`
The enetgy relased in the PROCESS approximately equals `(M)/(M-m)(r^(2)q^(2)B^(2))/(2m)`
The ENERGY released in the process apporximately equals `(M)/(M-m)((r^(2)q^(2)B^(2))/(2m))`

Answer :A::C


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