1.

A nucleuswithmass numberA =240and BE//A= 7.6 Me V breaksintotwofragmentseach ofA =120with BE//A=8.5 Me V .Calculatethe releasedenergy .

Answer»

Solution :Binding energy of nucleus with MASS NUMBER 240,
`BE_1 = 240 xx 7.6 =1824 Me V`
Binding energy of two fragments
`BE_2 = 2 xx 120 × 85 = 2040 MeV`
`:.` Energy released = `BE_2 – BE_1`
= (2040 – 1824) MeV = 216 MeV


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