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a number consists of two digits whose sum is 8 if 18 is added to the number its digit are reveresed find the number |
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Answer» of the digit of the two digit NUMBER is x.then problem other number is (8−x)So,we get the equation10x+(8−x)+18=10(8−x)+x10x+8−x+18=80−10x+x9x+26=80−2618x=54x= 54/18x=3Then,The digit in tens PLACE is 3The digit in ones place is (8−3=5), then the number is 35 and when 18is added the result is 53 the digits INTERCHANGE their position in the new number.Then,We get the number is 35. |
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