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A number cube has it side numbers as 12467 and 5 if the wine is thrown once what is probility of rolling an odd no​

Answer»

Answer:

\frac{<klux>1</klux>}{2}

Step-by-step explanation:

P(E)=\frac{No. of <klux>POSSIBLE</klux> <klux>OUTCOMES</klux>}{Total no. of outcomes}

possible outcomes =1;7;5

No. of possible outcomes =3

total no. of outcomes = 6

P(odd no.) = \frac{3}{6}

                 =\frac{1}{2}


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