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A number is selected at random from the numbers 1 to 30. The probability that it is a prime number isA. \(\frac{2}3\)B. \(\frac{1}6\)C. \(\frac{1}3\)D.\(\frac{11}{30}\) |
Answer» Total numbers of elementary events are: 30 Let E be the event of selecting a prime number Favorable outcomes are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29 Numbers of favorable outcomes are: 10 P (prime number) = P (E) = \(\frac{10}{30}\) = \(\frac{1}{3}\) |
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