1.

A number is selected at random from the numbers 1 to 30. The probability that it is a prime number isA. \(\frac{2}3\)B. \(\frac{1}6\)C. \(\frac{1}3\)D.\(\frac{11}{30}\)

Answer»

Total numbers of elementary events are: 30 

Let E be the event of selecting a prime number 

Favorable outcomes are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29 

Numbers of favorable outcomes are: 10 

P (prime number) = P (E) = \(\frac{10}{30}\) = \(\frac{1}{3}\)



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