

InterviewSolution
Saved Bookmarks
1. |
A number is selected at random from the numbers 3, 5, 5, 7, 7, 7, 9, 9, 9, 9 The probability that the selected number is their average isA \(\frac{1}{10}\)B \(\frac{3}{10}\)C \(\frac{7}{10}\)D \(\frac{9}{10}\) |
Answer» Total numbers of elementary events are: 10 Let E be the event of getting selected number being the average Favorable outcome is = \(\frac{70}{10}\) = 7 Average = total of observations/ numbers of observation Total of observations = 3+ 5+ 5+ 7+ 7+ 7+ 9+ 9 + 9+ 9 = 70 Numbers of observation = 7 Numbers of favorable outcomes are: 3 P ( selecting average number) = P (E) = \(\frac{3}{10}\) |
|