A number N_(0) of atoms of a radio active element are placed inside a closed volume. The radioactive decay constant for the nucleus of this element is lambda_(1). The daughter nucleus that form as a result of the decay process are assumed to be radioactive too with a radioactive decay constant lambda_(2). Determine the time variation of the number of such nucleus. Consider two limiting cases lambda_(1) gt gtlambda_(2) and lambda_(1) lt lt lambda_(2).

A number N_(0) of atoms of a radio active element are placed inside a

1.	A number N_(0) of atoms of a radio active element are placed inside a closed volume. The radioactive decay constant for the nucleus of this element is lambda_(1). The daughter nucleus that form as a result of the decay process are assumed to be radioactive too with a radioactive decay constant lambda_(2). Determine the time variation of the number of such nucleus. Consider two limiting cases lambda_(1) gt gtlambda_(2) and lambda_(1) lt lt lambda_(2).
Answer» ANSWER :`[N_(0)e^(-lambda_(2)t).(lambda_(1)N_(0))/(lambda_(2))(t-e^(-lambda_(2)t))]`

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