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A number of identical cells, n, each of emf epsi , internal resistance r connected in series are charged by a d.c. source of emf epsi , using a resistor R.(i)Draw the circuit arrangement.(ii) Deduce the expressions for (a) the charging current and (b) the potential difference across the combination of the cells. |
Answer» Solution : (a) The TOTAL internal resistance of n CELLS in series = nr Total resistance of entire circuit = R + nr Total emf of n cells in series = `n epsi` ` therefore `The charging CURRENT ` = ((epsi. - n espi))/((R + nr ))` (b) The potential DIFFERENCE across the combination of the cells ` V=n epsi + I.(nr)`, where I is the charging current. |
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