1.

A number was chosen at random from the first 300 three digits natural number. Find the probability of it ending with a zero.A. `(1)/(15)`B. `(1)/(25)`C. `(1)/(10)`D. `(1)/(20)`

Answer» Let the number be x, `100lexle399`.
A number ending with a 0 is divisible by 10.
Least value of x, divisible by 10=100=10(10).
Greatest value of x, divisible by 10=390=10(39)
Number of values of x divisible by 10 = number of numbers from 10 to 39 =30
`:.` Required probability `=(30)/(300)=(1)/(10)`.


Discussion

No Comment Found

Related InterviewSolutions