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A number was chosen at random from the first 300 three digits natural number. Find the probability of it ending with a zero.A. `(1)/(15)`B. `(1)/(25)`C. `(1)/(10)`D. `(1)/(20)` |
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Answer» Let the number be x, `100lexle399`. A number ending with a 0 is divisible by 10. Least value of x, divisible by 10=100=10(10). Greatest value of x, divisible by 10=390=10(39) Number of values of x divisible by 10 = number of numbers from 10 to 39 =30 `:.` Required probability `=(30)/(300)=(1)/(10)`. |
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