A nut is placed in a nut cracker at 5 cm from the fixed end. If the force experienced by the nut is 100 N when a force of 20 N is applied at the free end of the nut cracker, find the length of the nut cracker.

A nut is placed in a nut cracker at 5 cm from the fixed end. If the fo

1.	A nut is placed in a nut cracker at 5 cm from the fixed end. If the force experienced by the nut is 100 N when a force of 20 N is applied at the free end of the nut cracker, find the length of the nut cracker.
Answer» 5 25 15 20 Solution : Mechanical advantage `=("Load")/("EFFORT")=("Effort ARM")/("Load arm")` Therefore, `(100)/(20)=("Effort arm")/(5)` `implies` Effort arm =25 cm HENCE, the correct OPTIONS is (b).