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                                    A nut is placed in a nut cracker at 5 cm from the fixed end. If the force experienced by the nut is 100 N when a force of 20 N is applied at the free end of the nut cracker, find the length of the nut cracker.A. 5B. 25C. 15D. 20 | 
                            
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Answer» Correct Answer - B Mechanical advantage `=("Load")/("Effort")=("Effort arm")/("Load arm")` Therefore, `(100)/(20)=("Effort arm")/(5)` `implies` Effort arm =25 cm Hence, the correct options is (b).  | 
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