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A p-n diode is used in a half wave rectifier with a load resistance of 1000Omega . If the forward resistance (r_f) of diode is 10 Omega , calculate the efficiency of this half wave rectifier. |
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Answer» SOLUTION :LOAD resistance `R_L= 1000 Omega `, Forward resistance of the diode `= r_f= 10 Omega `. Efficiency of half wave rectifier `[( 0.406 R_L)/( r_f+R_L)]= ( 0.406 XX 1000)/( 1010) = 0.4019.` The percentage efficiency of the half wave rectifier `eta ` = 40.19% |
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