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A p-n diode is used in a half wave rectifier with a load resistance of 1000 Omega.If the forward resistance (r_(f)) of diode is 10Omega calculate the efficiency of this half wave rectifier. |
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Answer» Solution :LOAD resistance `R_(L)= 1000Omega,` Forward resistance of the DIODE` =r_(f) = 10Omega` Efficiency of half WAVE rectifier `[(0.406R_(L))/(r_(f)+R_(L))]=(0.406xx1000)/(1010)=0.4019.` The PERCENTAGE efficiency of the half wave rectifier `eta=40.19%` |
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