1.

A p-n diode is used in a half wave rectifier with a load resistance of 1000 Omega.If the forward resistance (r_(f)) of diode is 10Omega calculate the efficiency of this half wave rectifier.

Answer»

Solution :LOAD resistance `R_(L)= 1000Omega,`
Forward resistance of the DIODE` =r_(f) = 10Omega`
Efficiency of half WAVE rectifier
`[(0.406R_(L))/(r_(f)+R_(L))]=(0.406xx1000)/(1010)=0.4019.`
The PERCENTAGE efficiency of the half wave rectifier `eta=40.19%`


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