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A p-n photodiode is fabricated from a semiconductor with hand gap of 2.8 eV . Can it detect a wavelength of 6000 n m ? |
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Answer» Solution :`E_(g)= 2.8 e V , lambda = 6000 NM= 6000 xx 10^(-9) `m `E = h upsilon = h ""(c)/(lambda) = (6.6 xx 10^(-34) xx 3 xx 10^(8))/(6000 xx 10^(-9)) = 3.315 xx 10^(-19) J = (3.315 xx 10^(-19))/(1.6 xx 10^(-19)) = 2.07 eV` No , Since `h upsilon` is less than `E_(g)` |
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