A p photon having 10.2 eV energy collides with a hydrogen atom in ground state inelastically. After few microseconds, one other photon having 15 eV collides with the same hydrogen atom, then a suitable detector can detect :

A p photon having 10.2 eV energy collides with a hydrogen atom in grou

1.	A p photon having 10.2 eV energy collides with a hydrogen atom in ground state inelastically. After few microseconds, one other photon having 15 eV collides with the same hydrogen atom, then a suitable detector can detect :
Answer» 1 photon of 3.4 EV and electron of 1.4 eV 1 photon of 3.4 e V 2 photon of energy 10.2 eV 1 photon of 10.2 eV and 1 electron of 1.4 eV Solution :Energy in first excited state of `H_(2)=10.2eV`. So first photon will EXCITE atom to first staet, then atom will return to ground state by emitting photon of energy 10.2eV. IONISATION energy of `H_(2)` atom =13.6eV So SECOND photon will ionise the atom and additional energy =15-13.6=1.4eV is carried by electron as its K.E. So photon of energy 10.2eV and electron of energy 1.4eV is ejected.

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A p photon having 10.2 eV energy collides with a hydrogen atom in ground state inelastically. After few microseconds, one other photon having 15 eV collides with the same hydrogen atom, then a suitable detector can detect :

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