Saved Bookmarks
| 1. |
A pair of adjacent coils has a mutual inductance of 1.5 H. If the current in one coil changes from 0 to 20 A in 0.5 s, what is the change of flux linkage with the other coil ? |
|
Answer» Solution :EMF induced in SECOND COIL is, `epsilon_2=-(dphi_2)/(DT)=-M(dI_1)/(dt) "" (because Phi_2=MI_1)` `therefore dphi_2=M(dI_1)` `therefore Deltaphi_2=M(DeltaI_1)` `therefore Deltaphi_2=(1.5)(20)=30` Wb |
|