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A pair of diceis thrown. Find the probability of getting the sum 8 or more, if 4 appears onthe first die. |
Answer» Here, `A = `Event that `4` appears on first die. `A = {(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)}`. `:. n(A) = 6` Let `B = `Event that sum of the dice is `8` or more. Then, `B = {(3,6),(6,3),(2,6),(6,2),(5,3),(3,5),(4,4),(4,5),(4,6)}` Now, `(AnnB) = {(4,4),(4,5),(4,6)}` `=>n(AnnB) = 3` `:.` Required probability , `P(B/A) = (n(AnnB) )/(n(A)) = 3/6= 1/2` |
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