A parabolic bow1 with its bottom at origin has the shape `y = (x^(2))/(20)` where `x` and `y` are in metre The maximum height at which a small mass m can be placed on the bowl without slipping is (coeff of static friction `0.5` .A. `1.25Nm`B. `2.5m`C. `1.0m`D. `4.0m`

A parabolic bow1 with its bottom at origin has the shape `y = (x^(2))/

1.	A parabolic bow1 with its bottom at origin has the shape `y = (x^(2))/(20)` where `x` and `y` are in metre The maximum height at which a small mass m can be placed on the bowl without slipping is (coeff of static friction `0.5` .A. `1.25Nm`B. `2.5m`C. `1.0m`D. `4.0m`
Answer» Correct Answer - a As `y =(x^(2))/(20) , (dy)/(dx) =(2x)/(20)` Angle of repose `theta_(r)` is such that `mu = tan theta_(r) = (dy)/(dx) = (2x)/(20) = (x)/(10)` `x = 10 mu = 10 xx 0.5 = 5m` Corresponding value of `y = (x^(2))/(20) = (5^(2))/(20) = 1.25m` .

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A parabolic bow1 with its bottom at origin has the shape `y = (x^(2))/(20)` where `x` and `y` are in metre The maximum height at which a small mass m can be placed on the bowl without slipping is (coeff of static friction `0.5` .A. `1.25Nm`B. `2.5m`C. `1.0m`D. `4.0m`

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