1.

A parachutist after bailing out falls 50 m without friction When parachute opens, he descends at 2 ms and reaches the ground with a speed of 3 m l At what height did he bailout ?

Answer»

191 m
182 m
293 m
111 m

Solution :For FREE fall `v^(2)=2xx9.8 xx50=980`
When parachute opens
`3^(2)=v^(2)-2xx2xxh`
4h=980-9 or `h=(971)/(4)`
Total HEIGHT `=(971)/(4)+50=(1171)/(4)PROP 293 m`


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