1.

A parallel beam of light (lambda =500) is incident at an angle alpha = 30^(@) with the normal to the slit plane in Young's double-slit experiment. Assume that the intensity due to each slit at any point on the screen is I_(0). Point O is equidistant from S_(1) and S_(2). The distance between slits is 1 mm. Then

Answer»

the INTENSITY at O is `4 I_(0)`
the intensity at is zero
the intensity at a POINT on the screen 1 m below O is `4 I_(0)`
the intensity at a point on the screen 1 m below O is zero

Solution :Path difference at point `O = d sin alpha = 0.5 mm`
CORRESPONDING PHASE difference,
`Delta phi = (2pi)/(lambda) XX Delta x`
`= (2 pi (0.5 xx 10^(-3)))/(5000 xx 10^(-10)) = 2000 pi = 2 pi xx 1000`
O is point corresponding to a maxima with the point at 1m below O corresponding to central maixma.


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