1.

A parallel beam of light of wavelength 5000 fot A is incident normally on a single slit of width 0.001 mm. The light is focussed by a convex lens on a screen placed in focal plane.The first minimum is formed for the angle of diffraction equal to :

Answer»

`0^(@)`
`15^(@)`
`30^(@)`
`60^(@)`

Solution :`a SIN THETA = n LAMBDA = lambda"because n = 1`
`therefore sin theta = (lambda)/(a) = 0.5`
`theta = 30^(@)`.


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