1.

A parallel beam of light of wavelength 6000 Å gets diffracted by a single slit of width 0.3 mm. The angular position of the first minima of differacted light is :

Answer»

`2 xx 10^(3)` rad
`3 xx 10^(3)` rad
`1.8 xx 10^(-3)` rad
`6 xx 10^(-3)` rad.

Solution :Given, `lambda = 6000 Å = 6000 xx 10^(-10) m` and `n = 0.3 MM = 0.3 xx 10^(-3) m`
`0.3 xx 10^(-3) xx sin theta = 6000 xx 10^(-10)`
`sin theta = 2 xx 10^(-3)`
or `theta = 2 xx 10^(-3)` rad.


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