1.

A parallel combination of 0.1 M Omega resistor and a 10 muF capacitor is connected across a 1.5V source of negligible resistance. The time required for the capacitor to get charged up to 0.75 V is approximately (in seconds).

Answer»

`oo`
`log_(e) 2`
`log_(10)2`
zero

Solution :B. For the capacitor to GET charged up to
0.75 V, the charge on the plates should
be as follow.

`q=CE[1-e^(-t//RC)]`
or `0.75 xx 10^(-5) = 10^(-5) xx 1.5 [1-e^(-t/(10^5 xx 10^(-5)))]`
or `1/2 = [1-e^(-t)] or e^(-t) = 1/2`
TAKING LOG on both SIDES, we get
`-t = -1n2 or t =0.693s`.


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