1.

A parallel monochromatic beam of light is incident normally on a formed on a screen placed perpendicular to the direction the incident beam. At the first minimum of diffraction pattern the phase difference between the rays coming from the two edge ofthe slit is _______ .

Answer»

0
`(pi)/(2)`
`pi`
`2 pi`

Solution :
Position of MINIMA is given by
d SIN `THETA = n lambda`
For first minimum, n =1
`:. ""delta = d sin theta = lambda`
Hence , plase difference
`Deltaphi = (2piDelta)/(lambda) =(2pi)/(lambda).lambda=2pi`


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