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A parallel plate air capacitor is connected to a battery. Its charge, potential difference, electric field and the stored energy between the plates are Q_0,V_0,E_0" and "U_0 respectively. Keeping the battery connection uncharged, the capacitor is completely filled with a dielectric material. The charge, potential difference, electric field and energy stored become Q,V,E and U respectively. Which of the following is correct? U gt U_0. |
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Answer» Solution :Energy stored in a capacitor `= (1)/(2)xx " capacitance " xx (" VOLTAGE ")^2` Since the voltage of the capacitor REMAINS constant but its capacitance incrases, so the energy stored in the capacitor will increase. Hence, `U gt U_0` is CORRECT. |
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