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A parallel plate capacitor has plates of area 0.080m^2 and a separation of 1.2 cm . A battery charges the plates to a potential difference of 120V and is then disconnected . A dielectric slap of thickness 4.0mm and dielectric constant 4.8 is then placed symmetricallybetween the plates (a) What is the capacitance with the slab in place ? What is the free charge q (c) before and (d) after the slap is inserted ? What is the magnitude of the electric field (e) in the space between the plates and dielectric and (f) in the electric itself? (g) with the slab in place, what is the potential difference across teh plates (h) How much external work is involved in inserting the slab? |
| Answer» SOLUTION :`a) 59 pF B) 80 pF c)7.1 nC d)7.1 nC e)10kV//m F)2.1 kV//m G)88V h) 0.11 MU F` | |