InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A parallel plate capacitor has square plate of side 5 cm and separated by a distance of 1 mm . (a) Calculate the capacitance of this capacitor . (b) If a 10 V battery is connected to the capacitor what is the charge stored in any one of the plates? ( The value of epsilon_(0)= 8.85 xx10^(-12)Nm^(2)C^(-2)). |
|
Answer» Solution :(A) The capacitance of the CAPACITOR is `C=(epsilon_(0)A)/(d) =(8.85xx10^(-12)xx25xx10^(-4))/(1XX10^(-3))=221.2xx10^(-13) F ` `C=22.2 xx10^(-12)F = 22.12 pF` (b) The charge STORED in any on of the plates is Q = CV Then `Q=22.12 xx10^(-12)xx10=221.2xx10^(-12)C = 221.2 PC` |
|