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A parallel plate capacitor in series with a resistance of 100 Omega, an inductor of 20 mH and and AC voltage source of variable frequency shows resonance at a frequency of (1250)/(pi)Hz. If this capacitor is charged by a DC voltage source to a voltage 25 V, what amount of charge will be stored in each plate of the capacitor ? |
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Answer» `0.2 mu C` `rArr 4PI^(2)upsilon_(r )^(2)=(1)/(LC)rArr C=(1)/(4pi^(2)upsilon_(r )^(2)L)` `rArr C=(pi^(2))/(4pi^(2)xx(1250)^(2)xx20xx10^(-3))=8XX10^(-6)F` Now, the capacitor is charged by a voltage source of 25 V, charge stored = Q = CV `=8xx10^(-6)xx25=200xx10^(-6)=0.2xx10^(-3)C` `therefore Q=0.2 mC` |
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