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A parallel plate capacitor is to be designed using a dielectric of dielectric constant 5, so as to have a dielectric strength of 10^(9) Vm^(-1). If the voltage rating of the capacitor is 12 kV, the minimum area of each plate required to have a capacitance of 80 pF is ......... |
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Answer» `10.5XX10^(-6) m^(2)` `:. D=(V)/(E)` `C= (K in_(0)A)/(d)` `:. A = (Cd)/(K in_(0))` `= (CV)/(KE in_(0))` `=(80xx10^(-12)xx12xx10^(3))/(5xx10^(9)xx8.85xx10^(-12))` `=21.69xx10^(-6)` `= 21.7xx10^(-6) m^(2)` Second Method : Q = CV `sigma A = CV` `:. sigma = (CV)/(A)` `E = (E_(0))/(K) ` but `E_(0)= (sigma)/(in_(0))` `:. E= (sigma)/(K in_(0))` From (1) `E = (CV)/(AK in_(0))` `:. A =(CV)/(EK in_(0))` `=(80xx10^(-12)xx12xx10^(3))/(5xx10^(9)xx8.85xx10^(-12))` `:. A = 21.69xx10^(-6)` `:. A = 21.7xx10^(-6) m^(2)` |
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