1.

A parallel plate capacitor of capacitance 10muF is connected to a cell of emf 10 V and is fully charged. Now a dielectric slab (k = 3) of thickness equal to the gap between the plates is completely filled in the gap, keeping the cell connected. During the filling process,

Answer»

the increase in charge on the capacitor is `200 muC` .
the heat PRODUCED is zero
energy SUPPLIED by the cell = increase in stored potential energy + work done on the person who is filling the dielectric SLAB.
energy supplied by the cell = increase in stored potentialenergy + work done on the person who is filling the dielectric slab + heat produced.

Solution :a., b., C.
Initial charge (before filling the dielectric slab) is `10 xx 10 = 100`
`muC`. Final charge (after filling the dielectric slab) is `10 xx 30 = 300 muC`.
Increasing in charge is `20 muC`.


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