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A parallel-plateair capacitorwhose platesare separatedby a distanced = 5.0 mm is firstchagredto potantialdufferebceV = 90 Vand then disconnecedfrom a dcvoltage the capacitordecreasesby eta= 1.0 %taking intoaccountthat theaveragenumber of ion pairsformedin air understandard contionsper unit volumeper unittime is equalto n_(1) = 5.0 cm^(-3) s^(-1) and thatthe givenvoltage correspondsto thesaturations current. |
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Answer» Solution :Ions PRODUCED will CAUSE charge to decay. Clearly, `eta CV ` = decrease of charge `= dotn_(i) e A DT = (epsilon_(0)A)/(d) V eta` or, `t = (epsilon_(0) V eta)/(dotn_(i) e d^(2)) = 4.6` DAYS Note, that `n_(p)` here, is the number of ion pairs produced. |
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