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A parallel platecapacitor of capacitance 90 pF is connected to a battery of emf 20 V. If a dielectricmaterial of dielectric constant K =(5)/(3) is inserted between the plates the magnitude of the charge will be : |
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Answer» `1.2 ` nC `= (5)/(3) xx90 xx10^(-12) xx20` `3000xx10^(-12)C = 3 n C `  Current INDUCED in dielectric `Q - Q (1- (1)/(K))` `= 3 n C (1-(1)/(5//3))` `= 3 (1-(3)/(5))n C ` `= 3xx(2)/(5) n C = 1.2 n C ` |
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