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A parallel stream of electrons accelerated by a potential difference V= 25 V falls normally on a diaphragm with two narrow slits separated by a distance d=50 mu m. Calculate the distance betweeb neighbouring maxima of the diffraction patterns on a screen located at a distance =100 cm from the slits. |
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Answer» Solution :From the Young slit formula `DELTAX=(l LAMBDA)/(d)=(l)/(d).(2piħ)/(sqrt(2meV))` SUBSTITUTION GIVES `Deltax= 4.90 mu m`. |
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