1.

A parallelplate capacitor is made of two circular plates separatedby a distanc of 5mm and with a dielectric of dielectric constant 2.2 between them . When the electric field in the dielectric is 3xx10^(4)V/m the charge density of the positive platewill be close to :

Answer»

`3xx10^(4) C//m^(2)`
`6XX10^(4) C//m^(2)`
`6 xx10^(-7) C//m^(2)`
`3xx10^(-7) C//m^(2)`

SOLUTION :Electric field between two PLATES of capacitor
`E = (sigma)/(K in_(0))`
`:. Sigma = KE in_(0) = 2.2 xx3xx10^(4) xx8.85 xx10^(-12)`
`= 58.41xx10^(-8) = 6 xx10^(-7) C //m^(2)`


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