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A pariticle is performing `SHM` of amplitude `"A"` and time period `"T"`. Find the time taken by the period to go from `0` to `A//2`. |
Answer» Let equation of `SHM` be `x = A sin omegat` when `x = 0`, `t = 0` when `x = A//2, A//2 = A sin omegat` or `sinomegat = 1//2, omegat = pi//6` `(2pi)/(T)t = pi//6t = T//12` Hence, time taken is `T//12`, where `T` is where `T` is time period of `SHM`. |
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