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A partical executing simple harmonic motion has amplitude of `1 m` and time period `2 s At t = 0`, net force on the partical is zero. Find the equation of displacement of the partical. |
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Answer» In the case SHM , `x = a sin (omega t + phi)` here, `a = 1 m, omega = (2 pi)/(T) = (2 pi)/(2) = pi rad//s` At `t = 0`, net force on the partical position at `t = 0`. `:. x = 0 at t = 0` `:. 0 = a sin (omega xx 0+ phi)` `implies phi = 0` `x = a sin omega t` `x = 1 xx sin omega t` `x = sin omega t` |
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