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A partical moves from a point `(-2hati + 5hatj)` to `(4hati + 3hatj)` when a force of (4hati + 3hatj) N` is applied . How much work has been done by the force?A. 8JB. 11JC. 5JD. 2J |
Answer» Correct Answer - c (c ) Position vectors of the particles are `r_(1)=12hati+5hatj "and" r^(2)=4hatj +3hatk` `therefore`Displacement of the particles, `Deltas=r_(2)-r_(1)` `=4hatj +3hatk-(-2hati+5hatj)=2hati-hatj+3hatk` Force on the particle ,`F=4hati +3hatj` N `therefore` work done, `W=F.Deltas=(4hati+3hatj).(2hati-hatj+3hatk)` `=8-35J` |
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