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A partical of `mass m = 1 kg` oscillates simple harmonically with angular frequency `1 rad//s`. Find the phase of the partical at `t = 1 s and 2 s`. Start calculating time when the partical moves up passing through the mean position. |
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Answer» We need to find `phi = omega t + phi_(0)` where `omega` is the angular frequency of SHM. Since, the partical moves up at the equilibrium possition at `t = 0`, we have `phi_(0) = 0, Then , phi = t rad` Substituting, `t= 1s, 2s, we have phi = t rad, 2rad` |
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