1.

A particle A moving with a certain velocity has a de Broglie wavelength of 1 A. If particle B has mass 25% of that A and velocity 75% of that of A, the de Broglie wavelength of B will be approximately

Answer»

`1Å`
`5.3Å`
`3Å`
`0.2Å`

SOLUTION :`lamda_(A)=H/(mv),lamda_(B)=h/(0.25mxx0.75v)`
`(lamda_(B))/(lamda_(A))=1/(0.25xx0.75)=5.3`
`thereforelamda_(B)=5.3lamda_A=5.3Å`


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