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A particle exceutes the motion describes by `x(t)=x_(0)(1-e^(-gammat)),tge0,x_(0)0`. The maximum and minimum values of `v(t)` areA. `x_(0)` and `0`B. `x_(0)gamma` and 0C. 0 and `-x_(0)gamma^(2)`D. `x_(0)^(1+e^(-gamma))` |
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Answer» Correct Answer - B `x(t)=x_(0)(1-e^(-gammat))` `v(t)=(dx(t))/(dt)=x_(0)gammae^(-gammat)` `a(t)=(dv(t))/(dt)=-x_(0)gamma^(2)e^(-gammat)` |
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