1.

A particle executes S.H.M. with amplitude 2 cm. At extreme position theforce is 4 N. The force acting on it at a position mid-way between the mean and extreme is :

Answer»

1 N
2 N
3 N
4 N

Solution :`a=omega^(2)y`.
`:.""F=ma=m omega^(2)y`.
`implies""F prop y`.
Thus when DISPLACEMENT is halved, then force also becomes half i.e., `(1)/(2)(4)=2N`.
HENCE correct CHOICE is (b).


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