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InterviewSolution
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A particle executes SHM along a straight line so that its period is 12 s. The time it takes in traversing a distance equal to half its amplitude from its equilibrium position isA. 6 sB. 4 sC. 2 sD. 1 s |
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Answer» Since, particle starts from mean position. `therefore" x=A sin omegat` `therefore" "(A)/(2)=A sin omegat_(0)" or " (1)/(2)=sin omegat_(0)` or `sin. (2pi)/(T)t_(0)=sin. (pi)/(6)` or `(2pi)/(T)t_(0)=(pi)/(6)` `therefore" "t_(0)=(T)/(12)=(12)/(12)=1s` |
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