1.

A particle executes simple harmonic motion with an amplitude of `10 cm` and time period `6 s`. At `t = 0` it is position `x = 5 cm` from mean postion and going towards positive `x-`direaction. Write the equation for the displacement `x` at time `L`. Find the magnitude of the acceleration of the particle at `t = 4 s`.

Answer» Correct Answer - `x = (10 cm) sin [((pi)/(3)s^(-1))t + (pi)/(6)]`
`(10)/(9)pi^(2) prop 11 cm//s^(2)`


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