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A particle executing a simple harmonic motion has a period of 6 sec. The time taken by the particle to move from the mean position to half the amplitude, starting from the mean position is : |
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Answer» `(3)/(2)`sec `y=r SIN omega t` `:.""( r )/(2)=r sin((2pi)/(T).t)` `(1)/(2)=sin((2pi)/(T).t)` `IMPLIES""(2pi)/(T).t=(pi)/(6)` `implies""t=(T)/(12)` `t=(6)/(12)=(1)/(2)s` So correct choice is b. |
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