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A particle executing SHM of amplitude 4 cm and `T=4 s` .The time taken by it to move from positive extreme position to half the amplitude isA. 1 sB. `(1)/(3)` sC. `(2)/(3)` sD. `sqrt((2)/(3))` s |
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Answer» Correct Answer - C (c)Equation of motion , `y= a"cos"omegat` `implies(a)/(2)=a "cos"omegatimpliesomegat=(pi)/(3)` `implies (2pit)/(T)=(pi)/(3)impliest=((pi)/(3)xxT)/(2pi)=(4)/(3xx2)=(2)/(3) s` |
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